1=0.05x^2

Solution for 1=0.05x^2 equation:

1=0.05x^2

We move all terms to the left:

1-(0.05x^2)=0

We get rid of parentheses

-0.05x^2+1=0

a = -0.05; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-0.05)·1
Δ = 0.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.2}}{2*-0.05}=\frac{0-\sqrt{0.2}}{-0.1}
=-\frac{\sqrt{}}{-0.1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.2}}{2*-0.05}=\frac{0+\sqrt{0.2}}{-0.1}
=\frac{\sqrt{}}{-0.1}
$